4(x-1/2)^2=35

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Solution for 4(x-1/2)^2=35 equation: 


x in (-oo:+oo)

4*(x-(1/2))^2 = 35 // - 35

4*(x-(1/2))^2-35 = 0

4*(x-1/2)^2-35 = 0

4*(x-1/2)^2-35 = 0

4*x^2-4*x-34 = 0

4*x^2-4*x-34 = 0

2*(2*x^2-2*x-17) = 0

2*x^2-2*x-17 = 0

DELTA = (-2)^2-(-17*2*4)

DELTA = 140

DELTA > 0

x = (140^(1/2)+2)/(2*2) or x = (2-140^(1/2))/(2*2)

x = (2*35^(1/2)+2)/4 or x = (2-2*35^(1/2))/4

2*(x-((2-2*35^(1/2))/4))*(x-((2*35^(1/2)+2)/4)) = 0

2*(x-((2-2*35^(1/2))/4))*(x-((2*35^(1/2)+2)/4)) = 0

( 2 )

2 = 0

x belongs to the empty set

( x-((2*35^(1/2)+2)/4) )

x-((2*35^(1/2)+2)/4) = 0 // + (2*35^(1/2)+2)/4

x = (2*35^(1/2)+2)/4

( x-((2-2*35^(1/2))/4) )

x-((2-2*35^(1/2))/4) = 0 // + (2-2*35^(1/2))/4

x = (2-2*35^(1/2))/4

x in { (2*35^(1/2)+2)/4, (2-2*35^(1/2))/4 }

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